ENGLEWOOD, Colo. - Denver Broncos cornerback Dominique Rodgers-Cromartie was named AFC Defensive Player of the Week, the NFL informed the Broncos on Wednesday.
Rodgers-Cromartie totaled five tackles, three passes defensed and an interception returned 75-yards for a touchdown in Denver’s 45-21 win against the Washington Redskins on Sunday.
His touchdown, which came with just over two minutes remaining in the game, represented the sixth-longest pick-six in team history.
Rodgers-Cromartie signed on with the Broncos as a free agent in this past offseason. In his sixth-year, Rodgers-Cromartie, has totaled an NFL-high 94 passes defensed since he entered the NFL in 2008. He also owns the third-most interceptions returned for touchdowns at five during that span.
The award represents the second such honor of Rodgers-Cromartie’s career as he was named NFC Defensive Player of the Week on Oct. 11, 2009. Then as a member of the Arizona Cardinals, he picked off Houston Texans quarterback Matt Schaub and returned the interception 49-yards for the game-winning score.
The award also marks the 26th time a Bronco has been named AFC Defensive Player of the Week since the award was initiated in 1984.
Rodgers-Cromartie joins quarterback Peyton Manning and return specialist Trindon Holliday as Broncos to earn conference player of the week accolades this season. Manning won in weeks 1 and 3, Holliday won in week 2.
As the Broncos enter their bye week at 7-1, they will return to face a tough schedule where three out of their next four games will be on the road. Denver travels to San Diego, hosts the undefeated Kansas City, then are at New England and at Kansas City.